First slide

Position Path Length (Distance) And Displacement

Question

A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time, the particle goes up is

Easy

A

1,.25 J
B

0 .5 J
C

-0.5J
D

-1.25J

Solution

Maximum height attained by the particle
$\begin{array}{l} h = \frac{u^{2}}{2 g} = \frac{(5)^{2}}{2 \times 10} = \frac{5}{4} m \\ W = - mgh = - 0 \cdot 1 \times 10 \times (5 / 4) = - 1 \cdot 25 J \end{array}$

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