First slide

Work done by Diff type of forces

Question

A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up is :

Easy

A

1.25 J
B

0.5 J
C

- 0.5 J
D

- 1.25 J

Solution

Maximum height $= \frac{u^{2}}{2 g} = \frac{(5)^{2}}{2 (10)} = 1 .25 m$
W_gravity = -mgh = -1.25J

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