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A particle of mass 2 gm and a charge 1 μC is held at rest on a frictionless horizontal surface at a distance of 1 metre from a fixed charge of 1 mC. If the particle is released it will be repelled, The speed of the particle when it is at a distance of 10 metres from the fixed charge is

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a

100 m/s

b

90 m/s

c

60 m/s

d

45 m/s

answer is B.

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Detailed Solution

The change in potential energy of the charges=q1q24πε01r1−1r2=9×1091×10−610−311−110=9×910=8⋅1JThis is equal to the gain is kinetic energy. Let u be the velocity of the particle. Then12mv2=8⋅1 or 12×2×10−3v2=8⋅1Solving, ne get v = 90 m/s..

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