Questions
A particle of mass 10 gm is describing S.H.M. along a straight line with period of 2 sec and amplitude of 10 cm. Its kinetic energy when it is at 5 cm from its equilibrium position is
a
37.5π2ergs
b
3.75π2ergs
c
375π2ergs
d
0.375π2ergs
detailed solution
Correct option is C
Kinetic energy K=12mω2(a2−y2)=12×10×2π22[102−52] =375 π2ergsTalk to our academic expert!
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When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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