A particle of mass 10 gm is describing S.H.M. along a straight line with period of 2 sec and amplitude of 10 cm. Its kinetic energy when it is at 5 cm from its equilibrium position is

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37.5π2ergs

3.75π2ergs

375π2ergs

0.375π2ergs

answer is C.

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Detailed Solution

Kinetic energy K=12mω2(a2−y2)=12×10×2π22[102−52] =375 π2ergs

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