First slide

Simple harmonic motion

Question

A particle of mass 10 gm is describing S.H.M. along a straight line with period of 2 sec and amplitude of 10 cm. Its kinetic energy when it is at 5 cm from its equilibrium position is

Moderate

A

$37 .5 π^{2} ergs$
B

$3 .75 π^{2} ergs$
C

$375 π^{2} ergs$
D

$0 .375 π^{2} ergs$

Solution

Kinetic energy $K = \frac{1}{2} {mω}^{2} (a^{2} - y^{2})$
$= \frac{1}{2} \times 10 \times {(\frac{2 π}{2})}^{2} [10^{2} - 5^{2}]$ $= 375 π^{2} ergs$

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