First slide

Location of centre on mass for multiple point masses

Question

A particle of mass 2 gm is placed at point A(-6 cm, 0), a second particle of mass 4 gm is placed at point (3 cm, 0). A third particle of mass m is placed at the origin O. What should be the value of ‘m’ so that centre of mass of the system lies at the origin?

Easy

A
4 gm
B
8 gm
C
5 gm
D
All of the above options are true

Solution

Present position of center of mass
$\frac{2 \times (- 6) + 4 \times (3) + m \times 0}{2 + 4 + m} = 0 so center of mass is at the origin at it is independent of m$

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