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Q.

A particle of mass 2 gm is placed at point A(-6 cm, 0), a second particle of mass 4 gm is placed at point (3 cm, 0). A third particle of mass m is placed at the origin O. What should be the value of ‘m’ so that centre of mass of the system lies at the origin?

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a

b

c

d

answer is D.

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Detailed Solution

Present position of center of mass 2×-6+4×3+m×02+4+m=0 so center of mass is at the origin at it is independent of m
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