First slide
Work
Question

A particle of mass 100 gm thrown vertically upwards with a speed of  5 m/s.  The work done by the force of gravity during the time, the particle goes up is

Moderate
Solution

     Work done by gravity   =Ve
   from work energy theorem,  work done = change in KE initial velocity = 5m/s final velocity = 0 mass m =1001000kg   W   =    K.Efinal-KEinitial W   = 0-  12mv2 W=-121001000 52 W=-1.25 joule Here  gravity is opposite to the displacement and hence the work done by gravity is equal to negative  of ptential energy  when the body moves up. 
   
           

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