Questions
A particle of mass 100 gm thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time, the particle goes up is
detailed solution
Correct option is C
Work done by gravity =− Ve from work energy theorem, work done = change in KE initial velocity = 5m/s final velocity = 0 mass m =1001000kg W = K.Efinal-KEinitial W = 0- 12 mv2 W=- 121001000 52 W=-1.25 joule Here gravity is opposite to the displacement and hence the work done by gravity is equal to negative of ptential energy when the body moves up.Talk to our academic expert!
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