A particle of mass 50 gram executing simple harmonic motion with amplitude of 5m.  The maximum value of  force acting on the particle during the course of oscillation  with an angular  frequency of 10 rad/s is

The force responsible for simple harmonic motion is given by F=mω2x . here x is displacement From the  question mass= m=50 g= 0.05 kg ,angular velocity ω=10  rad/s  , amplitude=  A=5   mSubstituting these in maximum values of force, put x=A  to get maximum value of force    F=mω2A ,on substituting the given values we get F=0.05×102×5=25N=maximum value of  force acting on the particle during the course of oscillation