A particle of mass $$50$$ gram executing simple harmonic motion with amplitude of $$5m$$. The maximum value of force acting on the particle during the course of oscillation with an angular frequency of $$10$$ $$rad/s$$ is

Question

A particle of mass $$50$$ gram executing simple harmonic motion with amplitude of $$5m$$.  The maximum value of  force acting on the particle during the course of oscillation  with an angular  frequency of $$10$$ $$rad/s$$ is

Infinity Learn · Accepted Answer

The force responsible for simple harmonic motion is given by $$F=m$$ω$$2x$$ . here x is displacement From the  question $$mass=$$ $$m=50$$ $$g=$$ $$0.05$$ kg ,angular velocity ω$$=10$$  $$rad/s$$  , $$amplitude=$$  $$A=5$$   mSubstituting these in maximum values of force, put $$x=A$$  to get maximum value of force    $$F=m$$ω$$2A$$ ,on substituting the given values we get $$F=0.05$$×$$102$$×$$5=25N=maximum$$ value of  force acting on the particle during the course of oscillation

A particle of mass 50 gram executing simple harmonic motion with amplitude of 5m. The maximum value of force acting on the particle during the course of oscillation with an angular frequency of 10 rad/s is

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