First slide

Simple harmonic motion

Question

A particle of mass 10 grams is executing simple harmonic motion with an amplitude of 0.5 m and periodic time of $(π / 5)$ seconds. The maximum value of the force acting on the particle is

Moderate

A

25 N
B

5 N
C

2.5 N
D

0.5 N

Solution

Maximum force $= m ({aω}^{2}) = ma (\frac{4 π^{2}}{T^{2}})$
$= 0 .5 (\frac{4 π^{2}}{π^{2} / 25}) \times 0 .01 = 0 .5 N$

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