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Q.

A particle of mass 2 kg and charge 1mC is projected vertically with a velocity 10 ms-1. There is a uniform horizontal electric field of 104 NC-1. Then

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a

the horizontal range of the particle is 10 m

b

the time of flight of the particle is 2 s

c

the maximum height reached is 5 m

d

the horizontal range of the particle is 0

answer is A.

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Detailed Solution

Time of flight (t)=2ug=2×1010=2sH=u22g=1022×10=5mR=0+12qEmt2=12×10−3×104×2×22=10 m
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