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A particle of mass 2 kg is in equilibrium under the action of three forces ${\vec{F}}_{1}, {\vec{F}}_{2} and {\vec{F}}_{3}$ . If $| {\vec{F}}_{1} | = 3 N$ and $| {\vec{F}}_{2} | = 4 N$ and the angle between ${\vec{F}}_{1} and {\vec{F}}_{2} is 90^{o}$ . Find the acceleration of the particle after the force ${\vec{F}}_{3}$ is removed.

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3.2 m/s2

zero

2.5 m/s2

4 m/s2

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detailed solution

Correct option is C

a→=F→1+F→2m⇒a=32+422 ms2=2.5 ms2

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A particle of mass 2 kg is in equilibrium under the action of three forces F→1,F→2 and F→3. If |F→1|=3 N and |F→2|=4 N and the angle between F→1 and F→2 is 90o. Find the acceleration of the particle after the force F→3 is removed.

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