First slide

Third law

Question

A particle of mass 2 kg is in equilibrium under the action of three forces ${\vec{F}}_{1}, {\vec{F}}_{2} and {\vec{F}}_{3}$ . If $| {\vec{F}}_{1} | = 3 N$ and $| {\vec{F}}_{2} | = 4 N$ and the angle between ${\vec{F}}_{1} and {\vec{F}}_{2} is 90^{o}$ . Find the acceleration of the particle after the force ${\vec{F}}_{3}$ is removed.

Moderate

A

3.2 $m / s^{2}$
B

zero
C

2.5 $m / s^{2}$
D

4 $m / s^{2}$

Solution

$\vec{a} = \frac{{\vec{F}}_{1} + {\vec{F}}_{2}}{m} \Rightarrow a = \frac{\sqrt{3^{2} + 4^{2}}}{2} \frac{m}{s^{2}} = 2 .5 \frac{m}{s^{2}}$

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