A particle of mass $$0.1$$ kg is executing simple harmonic motion with amplitude $$20$$ cm along a straight line. Its maximum and minimum potential energies are $$0.8$$ J and $$0.6$$ J respectively. Then period of oscillation of the particle is

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Infinity Learn · Accepted Answer

$$(4)Energy$$  of  oscillation $$E=Umax$$−$$Umin=0.8$$−$$0.6J=0.2J$$∴    $$12$$  mω$$2A2=E$$  ⇒   ω$$=1A2Em$$∴    $$T=2$$πω$$=2$$π.$$Am2E$$ $$=2$$π ×  $$0.2$$  $$0.12$$ ×  $$0.2$$ $$sec$$$$=$$π$$5sec$$.

A particle of mass 0.1 kg is executing simple harmonic motion with amplitude 20 cm along a straight line. Its maximum and minimum potential energies are 0.8 J and 0.6 J respectively. Then period of oscillation of the particle is

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