A particle of mass 1 kg has velocity v1=(2t) i^ and another particle of mass 2 kg has velocity v2=(t2) j^. Match the following columns and mark the correct option from the codes given below.CodesA  B  C

FCM=F1+F2=m1a1+m2a2=(2i^+8j^)∴         FCM=4+64⇒FCM=68unit                 vCM=m1v1+m2v2m1+m2=(1)(4i^)+(2)(4j^)3=4i^+8j^3∴           vCM=1316+64=803unit                       s1=∫02v1dt=(4i^)                       s2=∫02v2dt=83j^Now,        sCM=m1s1+m2s2m1+m2=(1)(4i^)+283j^3=43i^+169j^∴        sCM=169+25681=209unitHence, A→q, B→r, C→p.