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A particle of mass 2kg initially at rest. A force acts on it whose magnitude changes with time. The force-time graph is shown below. The velocity of the particle at t=10 sec is
 

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a
75 ms−1
b
10 ms−1
c
50 ms−1
d
26 ms−1

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detailed solution

Correct option is C

2×V−2×0= Area under F−t graph ⇒2V=12×2×10+10×(4−2)+12(10+20)(6−4)+12×(10−6)×20⇒V=50m/s


Similar Questions

Figures I, II, III and IV depict variation of force with time. Select the figure(s) that depicts minimum impulse delivered.


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