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Q.

A particle of mass 2kg initially at rest. A force acts on it whose magnitude changes with time. The force-time graph is shown below. The velocity of the particle at t=10 sec is

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a

75 ms−1

b

10 ms−1

c

50 ms−1

d

26 ms−1

answer is C.

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Detailed Solution

2×V−2×0= Area under F−t graph ⇒2V=12×2×10+10×(4−2)+12(10+20)(6−4)+12×(10−6)×20⇒V=50m/s
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