A particle of mass 2kg initially at rest. A force acts on it whose magnitude changes with time. The force-time graph is shown below. The velocity of the particle at t=10 sec is

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75 ms−1

10 ms−1

50 ms−1

26 ms−1

answer is C.

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Detailed Solution

Area of the force time graph is impulse i.e., change in momentum.122×10+2×10+10+202+12×4×20mv−u = 10+20+30+402×v = 100v =50m/s

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