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Questions  

A particle of mass 2 kg located at the position  (i^+j^)m has a velocity 2(+i^-j^+k^)ms-1 Its angular momentum about Z-axis  (in kg-m2 s-1 )  is

a
+4
b
+8
c
-4
d
-8

detailed solution

Correct option is D

About origin, angular momentum will be L=m(r×v)=2i^j^k^1102-22=4i^-4j^-8k^Therefore, component of angular momentum about Z-axis would be  -8 kg·m2 s-1.

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