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Work done by Diff type of forces

A particle of mass 2 kg is moved along a line 3y=4x+10  under the influence of a force F=(4i^3j^)N . Find the work done by the force between the points 104,0  and 0,103


The particle is moved along the line 3y=4x+10,y=43x+103=mx+c , . Hence the slope of this line is 4/3. Again for the force acting  slope=tanθ=FyFx=34 . So product of the slopes= -1. We can say that the two lines are perpendicular to each other. 


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