A particle of mass 2 kg is moved along a line 3y=4x+10  under the influence of a force F→=(4i^−3j^)N . Find the work done by the force between the points −104,0  and 0,103

The particle is moved along the line 3y=4x+10,y=43x+103=mx+c , . Hence the slope of this line is 4/3. Again for the force acting  slope=tanθ=FyFx=−34 . So product of the slopes= -1. We can say that the two lines are perpendicular to each other. W=F.S.Cosθ=F.S.Cos900=0