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Q.

A particle of mass 2 kg moves with an initial velocity of (4i^+2j^)ms−1 on the x-y plane. A force F→=(2i^−8j^) acts on the particle. The initial position of the particle is (2 m, 3 m). Then for y = 3 m,

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a

Possible value of x is only x = 2 m

b

Possible value of x is not only x = 2 m, but there exists some other value of x also

c

Time taken is 2s

d

All of the above

answer is B.

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Detailed Solution

u→=4i^+2j^, a→=F→m=i^−4j^Let at any time, the coordinates be (x, y).x−2=uxt+12axt2⇒x−2=4t+12t2 and y−3=2t−124t2⇒ y−3=2t−2t2When y =3 m, t= 0, 1 s; when t = 0, x = 2 mWhen t = 1s, x = 6.5 m

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