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A particle of mass 2 kg moves with an initial velocity of v→=4i^+4j^ms−1. A constant force of F→=-20j^N is applied on the particle. Initially, the particle was at (0, 0). The x-coordinate of the particle when its y-coordinate again becomes zero is given by

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a

1.2 m

b

4.8 m

c

6.0 m

d

3.2 m

answer is D.

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Detailed Solution

a→=F→m=−10j^ms−12Displacement in y-directiony=ut+12at2⇒ 0=4×t×−12×10×t2t=45s ⇒ x=4t=4×45=3.2m

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A particle of mass 2 kg moves with an initial velocity of v→=4i^+4j^ms−1. A constant force of F→=-20j^N is applied on the particle. Initially, the particle was at (0, 0). The x-coordinate of the particle when its y-coordinate again becomes zero is given by