A particle of mass 0.2 kg is moving along x-axis and its displacement is given by x=2t2m , where t is time in second. Work done on the particle in 4 sec is

x=2t2∴  V=dxdt=4t  m/s.  At  t = 4s,V=16 m/sBy work energy theorem, work done = Kf−Ki=12×0.2×162−0J                                                                            = 256 Joule