Questions
A particle A of mass 10/7 kg is moving in the positive direction of x. Its initial position is x=0 & initial velocity is 1 m/s. the velocity at x=10, if its power varies with position as show in the figure
detailed solution
Correct option is A
Area under P-x graphs =∫1vpdx=∫1v(mdvdt)vdx ∫1vmv2 dv=[mv33]1v=107×3(v3−1) From graph : area =12(2+4)×10=30 ∴107×3(v3−1)=30 ∴ v=4m/sTalk to our academic expert!
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