Questions
A particle of mass 10kg is moving in a straight line. If its displacement, x with time t is given by , then the force acting on it at the end of 4 seconds is
detailed solution
Correct option is B
m=10kg,x=(t3−2t−10)m ⇒dxdt=v=3t2−2 ⇒dVdt2=a=6tAt the end of 4 seconds, a=6×4=24m/s2F=ma=10×24=240NTalk to our academic expert!
Similar Questions
A block of mass kg rests on a horizontal frictionless xy-plane. What would be the acceleration of the block if it is subjected to two forces as shown in figure?
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