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A particle of mass 10kg is moving in a straight line. If its displacement, x with time t is given by x=(t3−2t−10)m , then the force acting on it at the end of 4 seconds is

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a

24 N

b

240 N

c

300 N

d

1200 N

answer is B.

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Detailed Solution

m=10kg,x=(t3−2t−10)m ⇒dxdt=v=3t2−2 ⇒dVdt2=a=6tAt the end of 4 seconds, a=6×4=24m/s2F=ma=10×24=240N

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