A particle of mass 2 kg moving with a velocity of 3 m/s is acted upon by a force which changes its direction of motion by an angle of 90° without changing its speed. What is the magnitude of impulse experienced by the particle?

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6 N s

2 N s

32 Ns

62 Ns

answer is D.

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Detailed Solution

P→1=2×3i^=6i^, P→2=6j^I→=P→2−P→1=6j^−6i^or I=62+62=62 Ns

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