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Question

A particle of mass 0.5kg is moving in X-Y plane whose position at an instant ‘x’ is r=4sin2ti^+4(1cos2t)j^ m, where r is in metre and t is second. The kinetic energy of the particle at an instant ‘t’ is 

Moderate
Solution

r=4sin2ti^+4(1cos2t)j^v=8cos2t^+8sin2tj^KE=12mv2=12×0.5×82+82=12×0.5×128=32J

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