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A particle of mass 0.5 kg is at rest. A force F starts acting on the particle which varies according to the F-t graph shown in figure. Then kinetic energy of the particle at the end of 3 sec is 

a
530 J
b
625 J
c
67 J
d
250 J

detailed solution

Correct option is B

If ‘p’ be the momentum at the end of 3 sec, then change in momentum = Area under F-t graph ∴p-0=10 x 2 +12 x (3-2) x 10 kg-m/s⇒p=25 kg-m/s∴Kinetic energy =p22m=(25)22 x 0.5J=625 J

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Figures I, II, III and IV depict variation of force with time. Select the figure(s) that depicts minimum impulse delivered.


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