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Q.

A particle of mass 0.5 kg is at rest. A force F starts acting on the particle which varies according to the F-t graph shown in figure. Then kinetic energy of the particle at the end of 3 sec is

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a

530 J

b

625 J

c

67 J

d

250 J

answer is B.

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Detailed Solution

If ‘p’ be the momentum at the end of 3 sec, then change in momentum = Area under F-t graph ∴p-0=10 x 2 +12 x (3-2) x 10 kg-m/s⇒p=25 kg-m/s∴Kinetic energy =p22m=(25)22 x 0.5J=625 J

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