A particle of mass $$2$$ kg is at rest at point A (2m$$, $$1m). It is displaced to point B (3m$$, $$5m) under the action of a constant force F→$$=8i^+2j^N$$. Then the rate at which the kinetic energy of the particle is increasing at point B is

Question

A particle of mass $$2$$ kg is at rest at point A (2m$$, $$1m). It is displaced to point B (3m$$, $$5m) under the action of a constant force F→$$=8i^+2j^N$$. Then the rate at which the kinetic energy of the particle is increasing at point B is

Infinity Learn · Accepted Answer

Displacement d→$$=r$$→B−r→$$A=3$$−$$2i^+5$$−$$1j^$$ m⇒d→$$=i^+4j^mWork$$ done on the particle, $$W=F$$→.d→$$=8i^+2j^$$.$$i^+4j^$$⇒ $$W=16$$ JouleBy work $$-$$ energy theorem, $$12mV2=W$$⇒$$12.2$$.$$V2=16$$⇒$$V=4$$ $$m/sSince$$, velocity vector must lie along the force vector, we can write, V→$$=V$$.$$V^=V$$.$$F^=4688i^+2j^m/s$$∴ Rate of increase of kinetic energy $$=F$$→.V→$$=8i^+2j^.4688i^+2j^J/s=468$$ Watt

A particle of mass 2 kg is at rest at point A (2m, 1m). It is displaced to point B (3m, 5m) under the action of a constant force $\vec{F} = (8 \hat{i} + 2 \hat{j}) N$ . Then the rate at which the kinetic energy of the particle is increasing at point B is

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A particle of mass 2 kg is at rest at point A (2m, 1m). It is displaced to point B (3m, 5m) under the action of a constant force F→=8i^+2j^N. Then the rate at which the kinetic energy of the particle is increasing at point B is

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A particle of mass 2 kg is at rest at point A (2m, 1m). It is displaced to point B (3m, 5m) under the action of a constant force $\vec{F} = (8 \hat{i} + 2 \hat{j}) N$ . Then the rate at which the kinetic energy of the particle is increasing at point B is