Questions
A particle of mass 2 kg is on a smooth horizontal table and moves in a circular path of radius 0.6m. The height of the table from the ground is 0.8 m. If the angular speed of the particle is 12 rad s–1, the magnitude of its angular momentum about a point on the ground right under the centre of the circle is
detailed solution
Correct option is C
L = mVR ; m = 2kgV = rω = 0.6 × 12 = 7.2m/sTalk to our academic expert!
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A particle of mass m = 5 units is moving with a uniform speed , units in the XOY plane along the line y = x + 4. The magnitude of the angular momentum of the Particle about the origin is
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