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A particle of mass 2 kg starts moving from the origin along x-axis under the action of a force which is varying according to the graph shown in figure. Initial velocity of the particle is 2 m/s. Then work done by the force on the particle at t = 6 s is

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a

10 J

b

8 J

c

12 J

d

16 J

answer is C.

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Detailed Solution

Change is momentum = Area under F - t graph ∴ 2×v−2×2=8×2+12×(6−2)×(−6)⇒v=4 m/sBy work energy theorem, W=(KE)f−(KE)i=12×2×42−12×2×22⇒w=12 joule

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