Q.
A particle of mass 0 . 1kg is subjected to a force which varies with distance as shown in fig. (f). If it starts itsjourney from rest at x = 0, its velocity at x = 12 m is
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a
o m/s
b
202m/s
c
203m/s
d
40m/s
answer is D.
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Detailed Solution
The work done is equal to the area of F-x graph. Hence W=12×4×10+4×10+12×4×10 =80 joule The change in velocity is equal to work done. so 12mv2=W or 12×0⋅1×v2=80 or V2=1600 or V=40m/s
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