Q.

A particle of mass 1 kg is thrown vertically upward with speed 100 m/s. After 5 sec it  explodes into two parts. One part of mass 400 g comes back with speed 25 m/s, what is the speed of the other part just after explosion? (g=10 m/s2)

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a

600 m/s upward

b

100 m/s upward

c

100 m/s down ward

d

300 m/s upward

answer is B.

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Detailed Solution

v = u – gt = 100 – 10(5) = 100 – 50 = 50m/smv = m1v1 + m2v21000 x 50 = (400)(-25) + 600v250000 = -10000 + 600v260,000 = 600v2There fore v2 = 100 m / s
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