A particle of mass 1kg travels in a straight line with a velocity v=ax12 , a=5.  What is work done by a net force during its replacement from x=0 to x=2 m2

Given mass of particle m=1 kg Velocity v=ax12 Where  a = constant = 5At x=0, v=ax12=0 At x=2,v=ax12=5×212 According to work energy theorem. Work done = change in kinetic energyw=ΔKE=12mv2−0=12×1 W=12mv2−0=12×(5×212)2 =12×25×2=25 J