Questions
A particle of mass l0 gm is placed in a potential field given by V = (50 + 100) J/kg. The frequency of oscillation in cycle/sec is
detailed solution
Correct option is B
Potential energy U = mV⇒U = (50x2+100)10-2 F = -dUdx = -(100x)10-2⇒mω2x = -(100 ×10-2)x 10×10-3ω2x = 100×10-2 x⇒ω2 = 100 ∴ω = 10⇒f = ω2π = 102π= 5πTalk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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