A particle mass ‘m’ free to move in x-y plane is subjected to a force whose components are Fx= –kx and Fy= –ky, where ‘k’ is a constant. The particle is released when t = 0 at the point (2,3). The particle is in simple harmonic motion along the line represented by the equation.

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answer is B.

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Detailed Solution

Since and The particle will execute SHM parallel to x-axis and y-axis.Let and At t= 0, x= 2 and Also, Similarly at t= 0, y = 3 and

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