A particle mass ‘m’ free to move in $$x-y$$ plane is subjected to a force whose components are $$Fx=$$ –$$kx$$ and $$Fy=$$ –ky, where ‘k’ is a constant. The particle is released when t $$=$$ $$0$$ at the point (2$$,$$3). The particle is in simple harmonic motion along the line represented by the equation.

Question

A particle  mass ‘m’ free to move in $$x-y$$ plane is subjected to a force whose components are $$Fx=$$ –$$kx$$ and $$Fy=$$ –ky, where ‘k’ is a constant. The particle is released when t $$=$$ $$0$$ at the point (2$$,$$3). The particle is in simple harmonic motion along the line represented by the equation.

Infinity Learn · Accepted Answer

Since  and    The particle will execute SHM parallel to $$x-axis$$ and $$y-axis$$.Let and At $$t=$$ $$0$$, $$x=$$ $$2$$ and Also, Similarly at $$t=$$ $$0$$, y $$=$$ $$3$$ and

A particle mass ‘m’ free to move in x-y plane is subjected to a force whose components are F_x= –kx and F_y= –ky, where ‘k’ is a constant. The particle is released when t = 0 at the point (2,3). The particle is in simple harmonic motion along the line represented by the equation.

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A particle mass ‘m’ free to move in x-y plane is subjected to a force whose components are Fx= –kx and Fy= –ky, where ‘k’ is a constant. The particle is released when t = 0 at the point (2,3). The particle is in simple harmonic motion along the line represented by the equation.

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Ready to Test Your Skills?

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A particle mass ‘m’ free to move in x-y plane is subjected to a force whose components are F_x= –kx and F_y= –ky, where ‘k’ is a constant. The particle is released when t = 0 at the point (2,3). The particle is in simple harmonic motion along the line represented by the equation.