A particle of mass m is allowed to oscillate near the minimum of a vertical parabolic path having the equation x2 = 4ay . The angular frequency of small oscillation is given by
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a
gh
b
2gh
c
g2a
d
ga
answer is C.
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Detailed Solution
f=−mg sinθ for small ' θ ' sinθ=tanθf=−mg tanθ here tanθ=dydx=2x4a=x2af=−mgx2a=−mw2x