A particle of mass m is attached to a spring (of spring constant k) and has a natural angular frequency ω0 -An external force F (t) proportional to cosω t((ω≠ω0) is applied to the oscillator. The time displacement of the oscillator will be proportional to

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mω02−ω2

1m(ω02−ω2)

1m(ω12+ω2)

mω12+ω2

answer is B.

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Detailed Solution

For forced oscillation,x=x0sin(ωt+φ) and F=F0cosω twhere, x0=Fom (ωo2−ω2)∝1m(ωo2−ω2).

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