A particle of mass m and charge q has been projected from ground as shown in figure. Mark the correct statement(s). xy plane is vertical.

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The path of motion of the particle may be parabolic.

The path of motion of the particle may be a straight line.

Time of flight of the particle is 2usin ⁡θ/g .

Range of motion of the particle can be less than, greater than, or equal to u2sin ⁡2θ/g.

answer is A.

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Detailed Solution

Along x-axis,ux=ucos⁡θ⇒ax=−qEmAlong y-axis, uy=usin ⁡θ⇒ay=−g Equation of motion along x- and y-axes would be as follows: a is resultant acceleration. If a is opposite to u, i.e., α=θ, , then the path will be a straight line. For α≠θ,, the path will be parabolic. Time of flight remains unchanged as vertical motion is not affected by E⇀. Range of the particle in the present case is always less than u2 sin 2θ/g whatever may be the value of E.R=xt=ucos ⁡θ×2usin⁡ θg−12×qEm2usin⁡ θg2

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