A particle of mass m and charge q is placed in an electric field E which varies with time t as E= E0 sinωt. It will undergo simple harmonic motion of amplitude
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a
qE02mω2
b
qE0mω2
c
qE0mω
d
qE0mω2
answer is B.
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Detailed Solution
F= qE0sinωt when ωt =π2 accelartion will be maximummaximum acceleration is qE0m=ω2AA=qE0mω2