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Q.

A particle of mass ‘m ’ and charge ‘ q’ is projected into a region having a perpendicular uniform magnetic field ‘B’ of width d . Find the angle of deviation ‘θ ’ of the particle as it comes out of the magnetic field.

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a

sin−1dqBmv

b

sin−1Bqmvd

c

sin−1mvdqB

d

sin−1Bqmv

answer is A.

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Detailed Solution

The radius of the circular orbit is  r=mvqB−−−(1)The deviation 'θ' may be obtained from  sinθ=dr =dqBmv∴ θ=sin−1dqBmv .
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