A particle of mass ‘m ’ and charge ‘ q’ is projected into a region having a perpendicular uniform magnetic field ‘B’ of width d . Find the angle of deviation ‘θ ’ of the particle as it comes out of the magnetic field.
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a
sin−1dqBmv
b
sin−1Bqmvd
c
sin−1mvdqB
d
sin−1Bqmv
answer is A.
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Detailed Solution
The radius of the circular orbit is r=mvqB−−−(1)The deviation 'θ' may be obtained from sinθ=dr =dqBmv∴ θ=sin−1dqBmv .