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A particle of mass ‘m ’ and charge ‘ q’ is projected into a region having a perpendicular uniform magnetic field ‘B’ of width d . Find the angle of deviation ‘ $θ$ ’ of the particle as it comes out of the magnetic field.

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sin−1dqBmv

sin−1Bqmvd

sin−1mvdqB

sin−1Bqmv

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detailed solution

Correct option is A

The radius of the circular orbit is r=mvqB−−−(1)The deviation 'θ' may be obtained from sinθ=dr =dqBmv∴ θ=sin−1dqBmv .

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