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A particle of mass M and charge Q is projected in a uniform magnetic field of induction B in a direction perpendicular to the field. Then length of path traversed by the particle in time t=2πMQB is

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a
BQv2πR
b
Mv2R2πR
c
2πMVQB
d
BQ2πR

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detailed solution

Correct option is C

The particle will rotate in a cicular path of radius R = VMQB.So length of path traversed = 2πR =2πMVQB


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