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Q.

A particle of mass M and charge Q is projected in a uniform magnetic field of induction B in a direction perpendicular to the field. Then length of path traversed by the particle in time t=2πMQB is

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a

BQv2πR

b

Mv2R2πR

c

2πMVQB

d

BQ2πR

answer is C.

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Detailed Solution

The particle will rotate in a cicular path of radius R = VMQB.So length of path traversed = 2πR =2πMVQB

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