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Q.

A particle of mass ‘m’ and charge ‘q’ is projected with a velocity  v0 in a viscous medium, where a uniform and constant magnetic field of induction B  exists everywhere in a direction perpendicular to the direction of projection of the particle. The force of viscous drag on the particle is given by the law  f→=−bv→, where ‘b’ is a positive constant and  v→ is velocity of the particle. The distance travelled by the particle during a time interval from the instant of projection until velocity vector turns by 2π radians is  mv0b(1−enπbqB). Find ‘n’?

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Detailed Solution

Along the tangent net force is ​F=−bv​⇒mdvdt=−bvDue to magnetic force, the particle move in circular path of radius R.​∴v=dldt=Rdθdt ⇒mdv=−bRdθ⇒dv=−bmmvqBdθ⇒ V0Vdvv=−bqB 02πdθ⇒v=v0e−b2πqB​Now, again​F=−bv​⇒mvdvds=−bv⇒m∫v0vdv=−b∫0Sds​⇒mv−v0=−bSSo, distance covered S=mbv0−v=mv0b1−e2πbqB
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