Q.
A particle of mass ‘m’ and charge ‘q’ is projected with a velocity v0 in a viscous medium, where a uniform and constant magnetic field of induction B exists everywhere in a direction perpendicular to the direction of projection of the particle. The force of viscous drag on the particle is given by the law f→=−bv→, where ‘b’ is a positive constant and v→ is velocity of the particle. The distance travelled by the particle during a time interval from the instant of projection until velocity vector turns by 2π radians is mv0b(1−enπbqB). Find ‘n’?
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Detailed Solution
Along the tangent net force is F=−bv⇒mdvdt=−bvDue to magnetic force, the particle move in circular path of radius R.∴v=dldt=Rdθdt ⇒mdv=−bRdθ⇒dv=−bmmvqBdθ⇒ V0Vdvv=−bqB 02πdθ⇒v=v0e−b2πqBNow, againF=−bv⇒mvdvds=−bv⇒m∫v0vdv=−b∫0Sds⇒mv−v0=−bSSo, distance covered S=mbv0−v=mv0b1−e2πbqB
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