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Questions  

A particle of mass m executes simple harmonic motion with amplitude a and frequency v. The average kinetic energy during its motion from the position of equilibrium to the end is:

a
π2ma2v2
b
14ma2v2
c
4π2ma2v2
d
2π2ma2v2

detailed solution

Correct option is A

x=A cos ωt⇒v=dxdt=-Aω sin ωt                      KE=12mv2=12mA2ω2sin2ωt      Average KE=12mA2ω2=12mA2ω2×12                            =π2ma2v2

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