First slide
Applications of SHM
Question

A particle of mass m is executing oscillations about the origin on the x-axis. Its potential energy is U(x)=k[x]3, where k is a positive constant. If the amplitude of oscillation is a, then its time period T is

Difficult
Solution

U=k|x|3F==dUdx=3k|x|2        ...(i)
 Also, for SHM x=asinωt and  d2xdt2+ω2x=0
acceleration  =d2xdt2=ω2xF=ma
=md2xdt2=2x                                  ...(ii)
 From equation (i) & (ii) we get  ω=3kxm
T=2πω=2πm3kx=2πm3k(asinωt)T1a.

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