First slide
Simple harmonic motion
Question

A particle of mass m is executing oscillations about the origin on the X-axis with amplitude A. Its potential energy is given as U(x)=βx4, where β is a positive constant. The x-coordinate of the particle, where the potential energy is one-third of the kinetic energy, is

Difficult
Solution

U=βx4 (Given)   Umax=βA4 K(x)=UmaxU(x)=βA4βx4=βA4x4

    U(x)=13K(x)   (Given)     βx4=13βA4x4    x=±A2

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App