A particle of mass ‘m ’ is fixed to one end of light spring having force constant ‘k ’and unstretched length ‘l ’. The other end is fixed. The system is given an angular speed ω about the fixed end of the spring such that it rotates in a circle in gravity free space. Then the stretch in the spring is
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a
mlω2k+mω2
b
mlω2k−mω2
c
mlω2k−ωm
d
mlω2k+mω
answer is B.
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Detailed Solution
restoring force of a spring is F=-kx, --=(1) here k is force constant, x is displacement centrifugal force acting on the mass attached to spring is F=m(l+x)w2 ,---(2) here m is mass attached to the spring and l is unstretched length of spring equating above two equations 1 and 2 kx=mlω2+mxω2x(k−mω2)=mlω2 x=mlω2k−mω2