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Q.

A particle of mass m is fixed to one end of light spring of force constant k and unstretched length I as shown in fig. (5). The system is rotated about the other end ofthe spring with angular velocity o in gravity free space. The increase in length of the spring will be

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a

mlω2k

b

mlω2k−mω2

c

mlω2k+mω2

d

none of these

answer is B.

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Detailed Solution

Let the extension produced in the springs due to rotation be x. For the equilibrium of the bodykx=m(l+x)ω2or kx=mlω2+mxω2or kx−mxω2=mlω2x=mlω2k−mω2
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