A particle of mass m is fixed to one end of light spring of force constant k and unstretched length I as shown in fig. (5). The system is rotated about the other end ofthe spring with angular velocity o in gravity free space. The increase in length of the spring will be
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a
mlω2k
b
mlω2k−mω2
c
mlω2k+mω2
d
none of these
answer is B.
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Detailed Solution
Let the extension produced in the springs due to rotation be x. For the equilibrium of the bodykx=m(l+x)ω2or kx=mlω2+mxω2or kx−mxω2=mlω2x=mlω2k−mω2