Question

A particle of mass 5 m initially at rest explodes into three fragments with mass ratio g : 1 : 1. Two of the fragments each of mass m are found to move with a speed 60 m/s in mutually perpendicular directions.Then velocity of the third fragment (in m/s) will be

Moderate

Solution

I€t the velocity of third fragment b€ v. Applying the law of conservation of momentum, we have
$(m \times 60)^{2} + (m \times 60)^{2} = (3 m \times v)^{2} 7200 m^{2} = 9 m^{2} v^{2} V = 20 \sqrt{2} m / s$

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