First slide
Instantaneous acceleration
Question

A particle of mass m is initially situated at the point P inside a hemispherical surface of radius r as shown in figure. A horizontal acceleration of 

magnitude ao is suddenly produced on the particle in the horizontal direction. If gravitational acceleration is neglected, then time taken by particle to touch the sphere again is
where a is the angle which OP makes with radius OC.

Easy
Solution

Let the particle touches the sphere at point A as shown in figure.

Let PA=x. Now PB-x/2
From ΔOPB,cosα=PB/PO=PB/r
PB=rcosα
Therefore, x2=rcosα or x=2rcosα
But x=12a0t2
So,  t=2xa0=2×2rcosαa0
t=4rcosαa0

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App