A particle of mass m = 2kg executes SHM in xy plane between points A and B under the action of a force F→=Fxi^+Fyj^. Minimum time taken by the particle to move from A to B is 1 second. At t = 0, the particle is at x = 2 and y = 2. Then Fx as function of time t is

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−4π2sinπt

−4π2cosπt

4π2cosπt

None of these

answer is B.

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Detailed Solution

T = Time period = (1 + 1) S = 2S∴ ω = 2πT=π sec. Equation of SHM is x=Acosωt.∴ Fx=−mω2x=−mω2Acosωt=−2× π2 × 2 cos πt=−4π2cosπt

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