A particle of mass m $$=$$ $$2kg$$ executes SHM in xy plane between points A and B under the action of a force F→$$=Fxi^+Fyj^$$. Minimum time taken by the particle to move from A to B is $$1$$ second. At t $$=$$ $$0$$, the particle is at x $$=$$ $$2$$ and y $$=$$ $$2$$. Then Fx as function of time t is

Question

A particle of mass m $$=$$ $$2kg$$ executes SHM in xy plane between points A and B under the action of a force  F→$$=Fxi^+Fyj^$$. Minimum time taken by the particle to move from  A to B is $$1$$ second. At t $$=$$ $$0$$, the particle is at x $$=$$ $$2$$ and y $$=$$ $$2$$. Then Fx as function of time t is

Infinity Learn · Accepted Answer

T $$=$$ Time period $$=$$ (1$$ $$+$$ $$1) S $$=$$ $$2S$$∴  ω $$=$$ $$2$$$$π$$$$T=$$π $$sec$$. Equation of SHM is $$x=Acos$$ωt.∴    $$Fx=$$−mω$$2x=$$−mω$$2Acos$$ω$$t=$$−$$2$$×  π$$2$$ × $$2$$ $$cos$$ π$$t=$$−$$4$$$$π$$$$2cos$$$$π$$t

A particle of mass m = 2kg executes SHM in xy plane between points A and B under the action of a force $\vec{F} = (F_{x} \hat{i} + F_{y} \hat{j}) .$ Minimum time taken by the particle to move from A to B is 1 second. At t = 0, the particle is at x = 2 and y = 2. Then $F_{x}$ as function of time t is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A particle of mass m = 2kg executes SHM in xy plane between points A and B under the action of a force F→=Fxi^+Fyj^. Minimum time taken by the particle to move from A to B is 1 second. At t = 0, the particle is at x = 2 and y = 2. Then Fx as function of time t is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material