A particle of mass m kg moving with a velocity (3i^+2j^) ms-1 collides with a stationary body of mass M kg and finally moves with a velocity (-2i^+j^) ms-1. If mM=113, then

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the impulse is ±m(5i^+j^)kg.ms-1

the velocity of the M is 113(5i^+j^) ms-1

Both (a) and (b) are wrong

Both (a) and (b) are correct

answer is D.

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Detailed Solution

m(3i^+2j^)=m(-2i^+j^)+Mv∴ v=(5i^+j^)13 ms-1 (put, M=13m)Impulse, Jm=pf-pi=±m[(-2i^+j^)-(3i^+2j^)]∴ Jm=±m(5i^+j^)kg·ms-1

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