Questions
Particle A of mass moving along the x-axis with velocity collides elastically with another particle B at rest having mass . If the particles move along the x-axis after the collision, the change in de-Broglie wavelength of particle A, in terms of its de-Broglie wavelength before collision is :
detailed solution
Correct option is C
Conservation of momentum, m2V0+m30=m2VA+m3VB⇒3VA+2VB=3V0.....................1Coefficient of restitution,e=1=VA−VB0−V0⇒VA−VB=−V0.......................2Solving 1 and 2VA=V05Now, de broglie wavelength =λ=hmvSo, Initial wavelength of A=λi=hm2V0=λ0and Final wavelength of A=λf=hm2V05=5λ0Thus, Change in wavelength =△λ=λf−λi=4λ0In ground frame, m2 moves forward with 3V05−2V05=V05So λf=5λ0⇒Δ λ=4λ0Talk to our academic expert!
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